How To Manually Sort A List Of Numbers In Python?

Specs: Ubuntu 13.04, Python 3.3.1 Background: total beginner to Python, came across this 'manual sorting' problem. What I was asked to do: 'Have the user enter 3 numeric values

Solution 1:

For three items, you could use max and min to sort them:

a, b, c = 3, 1, 8

x = min(a, b, c)  # Smallest of the three
z = max(a, b, c)  # Largest of the three
y = (a + b + c) - (x + z)  # Since you have two of the three, you can solve for
                           # the third

print(a, b, c)
print(x, y, z)

If you don't want to use a sorting algorithm but can use lists, you could just pop out the smallest item each time and store it in a new list:

numbers = [1, 8, 9, 6, 2, 3, 1, 4, 5]
output = []

while numbers:
    smallest = min(numbers)
    index = numbers.index(smallest)
    output.append(numbers.pop(index))

print(output)

It's pretty inefficient, but it works.

Solution 2:

Using the Bubble Sort Algorithm:

num1=input("Enter a number: ")
num2=input("Enter another number: ")
num3=input("One more! ")
if num1<num2:
    temp=0
    temp=num1
    num1=num2
    num2=temp
if num1<num3:
    temp=0
    temp=num1
    num1=num3
    num3=temp
if num2<num3:
    temp=0
    temp=num2
    num2=num3
    num3=temp
print num3, num2, num1

Solution 3:

For Sorting a list manually, you can implement any kind of sorting algorithm like bubble sort, selection sort, insertion sort etc. so you can try the following code of bubble sort

#Bubble sort in python
def bubbleSort(numbers):
  for i in range(len(numbers)):
    for j in range(len(numbers)-i-1):
      if(numbers[j]>numbers[j+1]):
        temp=numbers[j]
        numbers[j]=numbers[j+1]
        numbers[j+1]=temp
        
#taking space seperated numbers as input in list
numbers=list(map(int, input().split(' ')));
bubbleSort(numbers)
print(numbers)