Multiple Parameters Url Pattern Django 2.0

I want to pass two parameters in my url pattern but i am getting error no-reverse match i.e 'projects'.While it works fine with only one parameter. here is main urls file- urlpatte

Solution 1:

No regex matching or additional model fields required to make it work.

urls.py

path('custom_page/<str:id1>/<str:id2>/', views.custom_page, name='custom_page'),

views.py

def custom_page(request, id1, id2):
    #use in view func or pass to template via context
    context = {}
    context['id1'] = id1
    context['id2'] = id2
    return render(request, 'custom_page.html', context=context)

custom_page.html

<div>{{id1}} {{id2}}</div>

Solution 2:

You can do something as below.

Old Way
(r'^view_url/(\d+)/(\d+)$', r'app_name.views.view_function'),
def view_function(request, param1, param2):
    """
    :param request:
    :param param1:
    :param param2:
    :return:
    """
    return render('/* template path and parameters */')

New Way
(r'^view_url/<int:param1>/<int:param2>$', r'app_name.views.view_function'),
def view_function(request, param1, param2):
    """
    :param request:
    :param param1:
    :param param2:
    :return:
    """
    return render('/* template path and parameters */')

For more details regex pattern in django 2.0 you can check django documentation link. https://docs.djangoproject.com/en/2.1/topics/http/urls/

Solution 3:

You can do what you want much more easily (without regular expressions) like so. You can find the documentation details here.

path('some_page/<int:project_id>/', views.some_page, name='some_page'),

And the function for my urlpattern above would look like this:

def some_page(request, project_id):
    project = Project.objects.get(id=project_id)
    return render(request, 'project.html', {'project': project})

Just remember that you need a Project model for this to work properly, with data in it.

And your template would be like:

<p>{{ project.modelfieldname1 }}</p>
<p>{{ project.modelfieldname2 }}</p>