Printing Elements Of Dictionary Line By Line

I have a dictionary in a file and i should write a python code to print the keys and values in seperate lines.(without using .keys() and .values(). For eg: dict={'the':'1', 'and':'

Solution 1:

line.split() splits on whitespace. You probably want line.split(':').

>>> "the:1".split()
['the:1']
>>> "the:1".split(':')
['the', '1']

Also note that

it = line.split(':')
k, v = it[0], it[1:]

can be simplified to

k, v = line.split(':')

edit: Well actually those two do different things, but as line.split() should only have 2 elements, k, v = line.split(':') will do what you want, whereas it[1:] would return ['1'] instead of '1'.

Though I guess to more gracefully handle parsing issues you could do:

it = line.split()
if len(it) != 2:
    print"Error!"
k, v = it[0], it[1]  # note it[1] and not it[1:]

Solution 2:

If you are trying to print the key values out of a dictionary in the same order as they appear in the file using a standard dict that won't work (python dict objects don't maintain order). Assuming you want to print by the value of the dicts values...

lines = ["the 1", "and 2"]
d = {}

for l inlines:
    k, v = l.split()
    d[k] = v

for key in sorted(d, key=d.get, reverse=True):
    print":".join([key, d[key]])

assuming you can use lambda and string concatenation.

lines = ["the 1", "and 2"]
d = {}

for l inlines:
    k, v = l.split()
    d[k] = v

for key in sorted(d, key=lambda k: d[k], reverse=True):
    print key + ":" + d[key]

with out lambda

for value, key insorted([(d[k], k) for k in d], reverse=True):
    print key + ":" + value

to make a function out of it

def lines_to_dict(lines):
    return_dict = {}
    for line inlines:
        key, value = line.split()
        return_dict[key] = value

    return return_dict

if __name__ == "__main__":

    lines = ["the 1", "and 2"]
    print lines_to_dict(lines)

Solution 3:

As long as the key/value are both strings, then you can parse the dictionary and extract the elements. Note, since this doesn't actually create the dictionary, duplicate elements and the order is preserved - which you may wish to account for.

import ast

text = '{"the":"1", "and":"2"}'
d = ast.parse(text).body[0].value
for k, v in zip(d.keys, d.values):
    print '{}:{}'.format(k.s, v.s)