Reading Config File As Dictionary In Flask

in /instance/app.cfg I've configured : test=test In my flask file app.py : with app.open_instance_resource('app.cfg') as f: config = f.read() print('config' , type(config

Solution 1:

Reading the flask doc it does not detail how to read values from configuration files, how is this achieved ?

You can read about it in flask's doc here (title "configuring-from-files")

open_instance_resource is only a shortcut to make deal with files which are located in "instance folder" (a special place where you can store deploy specific files). It's not supposed to be a way to get your config as a dict.

Flask stores his config variable(app.config) as a dict object. You can update it via a bunch of methods: from_envvar, from_pyfile, from_object etc. Look at the source code

One of the typical ways how people read config files in flask-based apps:

app = Flask('your_app')
...
app.config.from_pyfile(os.path.join(basedir, 'conf/api.conf'), silent=True)
...

After that, you can use your dict-like config object as you want:

...
logging_configuration = app.config.get('LOGGING')
if logging_configuration:
    logging.config.dictConfig(logging_configuration)
...

---

from flask import Flask
app = Flask(__name__)

import os

app.config.from_pyfile(os.path.join('.', 'conf/api.conf'), silent=True)

@app.route('/')defhello_world():
    return'Hello World! {}'.format(app.config.get('LOGGING'))

if __name__ == '__main__':
    app.run()

---

Solution 2:

If you do app.config.from_pyfile('app.cfg') you can obtain your config as a dictionary by dict(app.config).

However, this dictionary will contain the whole configuration for your app not only those variables which were set by the configuration file.