Cannot Understand The Output Of This Code: Python List To 1-d Numpy Array

I tried to create turn a python list into a numpy array, but got very unintuitive output. Certainly I did something wrong, but out of curiosity I would like to know why I got such

Solution 1:

You created a five dimensional array.

a = [1, 5, 3, 6, 2]
b = np.ndarray(a)
print(b.shape)

gives

(1, 5, 3, 6, 2)

The first argument of the np.ndarray is the shape of the array. Your probably wanted

b = np.array(a)
print(b)

which gives

[1 5 3 6 2]

Solution 2:

You've created a n-dimensional array whereby n = 5 which is the length of the array passed (which form the dimensions as explained here).

It's likely you're looking for:

np.array(a)

Those numbers are float 0.

Solution 3:

To create an array from a list, use: b = np.array(a). np.ndarray is another numpy class, and the first argument of the function is the shape of the array (hence the shape of your array being b.shape -> (1, 5, 3, 6, 2))

Solution 4:

np.ndarray(shape, dtype=float....) the argument require shape, so it will create a new array with shape (1, 5, 3, 6, 2) in your example

a = [1, 5, 3, 6, 2]
b = np.ndarray(a)
print(b.shape)

return

(1, 5, 3, 6, 2)

what you want is np.array

a = [1, 5, 3, 6, 2]
b = np.array(a)
print(b.shape)

return

(5,)