Dict Comprehension Python From List Of Lists

I have a list of lists and I am trying to make a dictionary from the lists. I know how to do it using this method. Creating a dictionary with list of lists in Python What I am try

Solution 1:

Unpacking and using zip followed by a dict comprehension to get the mapping with first elements seems readable.

result_dict = {first: rest for first, *rest in zip(*exampleList)}

Solution 2:

Unpack the values using zip(*exampleList) and create a dictionary using key value pair.

dicta = {k:[a, b] for k, a, b inzip(*exampleList)}
print(dicta)
# {'first': ['A', '1'], 'second': ['B', '2'], 'third': ['C', '3']}

If more lists:

dicta = {k:[*a] for k, *a inzip(*exampleList)}
# {'first': ['A', '1', 4], 'second': ['B', '2', 5], 'third': ['C', '3', 6]}

Solution 3:

Take care of the case when exampleList could be of any length..

exampleList = [['first','second','third'],['A','B','C'], ['1','2','3'],[4,5,6]]

z=list(zip(*exampleList[1:]))
d={k:list(z[i])  for i,k inenumerate(exampleList[0])}
print(d)

output

{'first': ['A', '1', 4], 'second': ['B', '2', 5], 'third': ['C', '3', 6]}

Solution 4:

If you don't care about lists vs tuples, it's as simple as using zip twice:

result_dict = dict(zip(example_list[0], zip(*example_list[1:])))

Otherwise, you'll need to through in a call to map:

result_dict = dict(zip(example_list[0], map(list, zip(*example_list[1:]))))

Solution 5:

The zip function might be what you are looking for.

exampleList = [['first','second','third'],['A','B','C'], ['1','2','3']]
d = {x: [y, z] for x, y, z inzip(*exampleList)}
print(d)
#{'first': ['A', '1'], 'second': ['B', '2'], 'third': ['C', '3']}