Running Function 5 Seconds After Pygtk Widget Is Shown
How to run function 5 seconds after pygtk widget is shown?
Solution 1:
You can use glib.timeout_add(interval, callback, ...) to periodically call a function.
If the function returns True then it will be called again after the interval; if the function return False then it will not be called again.
Here is a short example of adding a timeout after a widget's show event:
import pygtk
pygtk.require('2.0')
import gtk
import glib
deftimer_cb():
print"5 seconds elapsed."returnFalsedefshow_cb(widget, data=None):
glib.timeout_add(5000, timer_cb)
defdestroy_cb(widget, data=None):
gtk.main_quit()
defmain():
window = gtk.Window(gtk.WINDOW_TOPLEVEL)
window.connect("show", show_cb)
window.connect("destroy", destroy_cb)
window.show()
gtk.main()
if __name__ == "__main__":
main()
Solution 2:
If the time is not critical to be exact to the tenth of a second, use
glib.timeout_add_seconds(5, ..)
else as above.
timeout_add_seconds allows the system to align timeouts to other events, in the long run reducing CPU wakeups (especially if the timeout is reocurring) and save energy for the planet(!)
Post a Comment for "Running Function 5 Seconds After Pygtk Widget Is Shown"