Python List Index Out Of Range On Return Value Of Split
Solution 1:
I would guess you have a blank line somewhere in your file. If it runs through the data and then generates the exception the blank line will be at the end of your file.
Please insert
print len(line), line
before your
print line[1]
as a check to verify if this is the case.
You can always use this construct to test for blank lines and only process/print non-blank lines:
for line in f:line=line.strip()if line:# process/print line further
Solution 2:
When you are working with list and trying to get value at particular index, it is always safe to see in index is in the range
if len(list_of_elements) > index:
print list_of_elements[index]
See:
>>>list_of_elements = [1, 2, 3, 4]>>>len(list_of_elements)
4
>>>list_of_elements[1]
2
>>>list_of_elements[4]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
IndexError: list index out of range
>>>
Now you have to find out why your list did not contain as many elements as you expected
Answer :
import sys
if (len(sys.argv) > 1):
f = open(sys.argv[1], "r")
print"file opened"for line in f:
line = line.strip().strip('\n')
# Ensure that you are not working on empty lineif line:
data = line.split(",")
# Ensure that index is not out of rangeiflen(data) > 1: print data[1]
f.close()
Solution 3:
you probably have empty line(s) after your data, I ran your test code without them it worked as expected.
$ python t.py t.txt
file opened
389182.567389182.590389182.611389182.631389182.654
if you don't want to remove them, then simply check for empty lines.
for line in f:
if line.strip(): # strip will remove allleadingandtrailing whitespace such as'\n'or' 'bydefault
line = line.strip("\n ' '")
line = line.split(",")
print line[1]
Solution 4:
It can be useful to catch the exception an print the offending lines
for line in f:
line = line.strip("\n ' '")
line = line.split(",")
try:
print line[1]
except IndexError, e:
print e
print"line =", line
raise# if you don't wish to continue
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